Optimal. Leaf size=444 \[ \frac{3 i b e^{i c} \left (4 a^2+b^2\right ) \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-i d x^2\right )}{16 e}-\frac{3 i b e^{-i c} \left (4 a^2+b^2\right ) \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},i d x^2\right )}{16 e}+\frac{3 a b^2 e^{2 i c} 2^{-\frac{m}{2}-\frac{7}{2}} \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-2 i d x^2\right )}{e}+\frac{3 a b^2 e^{-2 i c} 2^{-\frac{m}{2}-\frac{7}{2}} \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},2 i d x^2\right )}{e}-\frac{i b^3 e^{3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-3 i d x^2\right )}{16 e}+\frac{i b^3 e^{-3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},3 i d x^2\right )}{16 e}+\frac{a \left (2 a^2+3 b^2\right ) (e x)^{m+1}}{2 e (m+1)} \]
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Rubi [A] time = 0.479603, antiderivative size = 444, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3403, 6, 3390, 2218, 3389} \[ \frac{3 i b e^{i c} \left (4 a^2+b^2\right ) \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-i d x^2\right )}{16 e}-\frac{3 i b e^{-i c} \left (4 a^2+b^2\right ) \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},i d x^2\right )}{16 e}+\frac{3 a b^2 e^{2 i c} 2^{-\frac{m}{2}-\frac{7}{2}} \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-2 i d x^2\right )}{e}+\frac{3 a b^2 e^{-2 i c} 2^{-\frac{m}{2}-\frac{7}{2}} \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},2 i d x^2\right )}{e}-\frac{i b^3 e^{3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (-i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-3 i d x^2\right )}{16 e}+\frac{i b^3 e^{-3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (i d x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},3 i d x^2\right )}{16 e}+\frac{a \left (2 a^2+3 b^2\right ) (e x)^{m+1}}{2 e (m+1)} \]
Antiderivative was successfully verified.
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Rule 3403
Rule 6
Rule 3390
Rule 2218
Rule 3389
Rubi steps
\begin{align*} \int (e x)^m \left (a+b \sin \left (c+d x^2\right )\right )^3 \, dx &=\int \left (a^3 (e x)^m+\frac{3}{2} a b^2 (e x)^m-\frac{3}{2} a b^2 (e x)^m \cos \left (2 c+2 d x^2\right )+3 a^2 b (e x)^m \sin \left (c+d x^2\right )+\frac{3}{4} b^3 (e x)^m \sin \left (c+d x^2\right )-\frac{1}{4} b^3 (e x)^m \sin \left (3 c+3 d x^2\right )\right ) \, dx\\ &=\int \left (\left (a^3+\frac{3 a b^2}{2}\right ) (e x)^m-\frac{3}{2} a b^2 (e x)^m \cos \left (2 c+2 d x^2\right )+3 a^2 b (e x)^m \sin \left (c+d x^2\right )+\frac{3}{4} b^3 (e x)^m \sin \left (c+d x^2\right )-\frac{1}{4} b^3 (e x)^m \sin \left (3 c+3 d x^2\right )\right ) \, dx\\ &=\int \left (\left (a^3+\frac{3 a b^2}{2}\right ) (e x)^m-\frac{3}{2} a b^2 (e x)^m \cos \left (2 c+2 d x^2\right )+\left (3 a^2 b+\frac{3 b^3}{4}\right ) (e x)^m \sin \left (c+d x^2\right )-\frac{1}{4} b^3 (e x)^m \sin \left (3 c+3 d x^2\right )\right ) \, dx\\ &=\frac{a \left (2 a^2+3 b^2\right ) (e x)^{1+m}}{2 e (1+m)}-\frac{1}{2} \left (3 a b^2\right ) \int (e x)^m \cos \left (2 c+2 d x^2\right ) \, dx-\frac{1}{4} b^3 \int (e x)^m \sin \left (3 c+3 d x^2\right ) \, dx+\frac{1}{4} \left (3 b \left (4 a^2+b^2\right )\right ) \int (e x)^m \sin \left (c+d x^2\right ) \, dx\\ &=\frac{a \left (2 a^2+3 b^2\right ) (e x)^{1+m}}{2 e (1+m)}-\frac{1}{4} \left (3 a b^2\right ) \int e^{-2 i c-2 i d x^2} (e x)^m \, dx-\frac{1}{4} \left (3 a b^2\right ) \int e^{2 i c+2 i d x^2} (e x)^m \, dx-\frac{1}{8} \left (i b^3\right ) \int e^{-3 i c-3 i d x^2} (e x)^m \, dx+\frac{1}{8} \left (i b^3\right ) \int e^{3 i c+3 i d x^2} (e x)^m \, dx+\frac{1}{8} \left (3 i b \left (4 a^2+b^2\right )\right ) \int e^{-i c-i d x^2} (e x)^m \, dx-\frac{1}{8} \left (3 i b \left (4 a^2+b^2\right )\right ) \int e^{i c+i d x^2} (e x)^m \, dx\\ &=\frac{a \left (2 a^2+3 b^2\right ) (e x)^{1+m}}{2 e (1+m)}+\frac{3 i b \left (4 a^2+b^2\right ) e^{i c} (e x)^{1+m} \left (-i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},-i d x^2\right )}{16 e}-\frac{3 i b \left (4 a^2+b^2\right ) e^{-i c} (e x)^{1+m} \left (i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},i d x^2\right )}{16 e}+\frac{3\ 2^{-\frac{7}{2}-\frac{m}{2}} a b^2 e^{2 i c} (e x)^{1+m} \left (-i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},-2 i d x^2\right )}{e}+\frac{3\ 2^{-\frac{7}{2}-\frac{m}{2}} a b^2 e^{-2 i c} (e x)^{1+m} \left (i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},2 i d x^2\right )}{e}-\frac{i 3^{-\frac{1}{2}-\frac{m}{2}} b^3 e^{3 i c} (e x)^{1+m} \left (-i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},-3 i d x^2\right )}{16 e}+\frac{i 3^{-\frac{1}{2}-\frac{m}{2}} b^3 e^{-3 i c} (e x)^{1+m} \left (i d x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},3 i d x^2\right )}{16 e}\\ \end{align*}
Mathematica [A] time = 8.56236, size = 373, normalized size = 0.84 \[ \frac{1}{16} i x (e x)^m \left (3 b e^{i c} \left (4 a^2+b^2\right ) \left (-i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},-i d x^2\right )-3 b e^{-i c} \left (4 a^2+b^2\right ) \left (i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},i d x^2\right )-3 i a b^2 e^{2 i c} 2^{\frac{1}{2}-\frac{m}{2}} \left (-i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},-2 i d x^2\right )-3 i a b^2 e^{-2 i c} 2^{\frac{1}{2}-\frac{m}{2}} \left (i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},2 i d x^2\right )-b^3 e^{3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (-i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},-3 i d x^2\right )+b^3 e^{-3 i c} 3^{-\frac{m}{2}-\frac{1}{2}} \left (i d x^2\right )^{-\frac{m}{2}-\frac{1}{2}} \text{Gamma}\left (\frac{m+1}{2},3 i d x^2\right )-\frac{8 i a \left (2 a^2+3 b^2\right )}{m+1}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.415, size = 0, normalized size = 0. \begin{align*} \int \left ( ex \right ) ^{m} \left ( a+b\sin \left ( d{x}^{2}+c \right ) \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.35579, size = 894, normalized size = 2.01 \begin{align*} \frac{24 \,{\left (2 \, a^{3} + 3 \, a b^{2}\right )} \left (e x\right )^{m} d x +{\left (b^{3} e m + b^{3} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (\frac{3 i \, d}{e^{2}}\right ) - 3 i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, 3 i \, d x^{2}\right ) +{\left (-9 i \, a b^{2} e m - 9 i \, a b^{2} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (\frac{2 i \, d}{e^{2}}\right ) - 2 i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, 2 i \, d x^{2}\right ) - 9 \,{\left ({\left (4 \, a^{2} b + b^{3}\right )} e m +{\left (4 \, a^{2} b + b^{3}\right )} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (\frac{i \, d}{e^{2}}\right ) - i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, i \, d x^{2}\right ) - 9 \,{\left ({\left (4 \, a^{2} b + b^{3}\right )} e m +{\left (4 \, a^{2} b + b^{3}\right )} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (-\frac{i \, d}{e^{2}}\right ) + i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, -i \, d x^{2}\right ) +{\left (9 i \, a b^{2} e m + 9 i \, a b^{2} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (-\frac{2 i \, d}{e^{2}}\right ) + 2 i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, -2 i \, d x^{2}\right ) +{\left (b^{3} e m + b^{3} e\right )} e^{\left (-\frac{1}{2} \,{\left (m - 1\right )} \log \left (-\frac{3 i \, d}{e^{2}}\right ) + 3 i \, c\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, -3 i \, d x^{2}\right )}{48 \,{\left (d m + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \left (a + b \sin{\left (c + d x^{2} \right )}\right )^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sin \left (d x^{2} + c\right ) + a\right )}^{3} \left (e x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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